• nickwitha_k (he/him)@lemmy.sdf.org
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      7 months ago

      In the hypothetical, if one were able to lick elemental hydrogen in its atomic, rather than molecular form, it would have a few potential effects. The one that would concern me most would be its aggressive reactivity, ripping hydrogens away from anything that it could in order to achieve stability. This would potentially cause tissue damage both from the deprotonation and shift in pH.

        • nickwitha_k (he/him)@lemmy.sdf.org
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          7 months ago

          It would be more likely a secondary or tertiary effect. That is, H• radicals ripped away from their parent molecules would leave •OH, •R, and •RNH radicals. These are unstable and highly reactive, “desiring” to have that stable electron configuration. Likely, this will result in electrons being shifted to bring in more stable species, like OH-. Overall, we’re looking at effectively a deprotonation of the saliva, with extra intermediary steps to stabilize the radicals.

            • nickwitha_k (he/him)@lemmy.sdf.org
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              7 months ago

              Neutral as far as pH is concerned, yes. However, radicals tend to be very reactive due to their valance not being full. I am a bit rusty, TBH, as I’m about a decade and a half out of uni but, the best way to predict the products of the reaction is to look at the high-level of the equation:

              H• (excess) + H••OH + H••R + H••N-R -> H2(g) + •OH + •R + •N-R

              All of the products of the initial reaction here are radicals except for the H2 molecules. They all are going to further react to form more stable species with full valances, with possible exception being the molecular hydrogen. Because the elemental hydrogen is introduced as a radical rather than protons (H+ ions) in the solution, the final products are likely to be more negatively charged, neutral, and/or have some interesting hydrogen additions, especially in the hydrocarbons and amino acids.

              For example, there could be reactions like: R• + •OH + •N-R -> R-OH + HO-N-R

              Overall, however, the amount of free hydrogen/protons is likely to be reduced as they are effectively removed from solution as hydrogen gas.

                • nickwitha_k (he/him)@lemmy.sdf.org
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                  4 months ago

                  No. I think that you’re absolutely correct. The products should have charge conserved. After initial attack of hydrocarbons by H• radicals, H2 is likely to be a significant product. Supposing STP, it would likely remove itself from solution, leaving the fresh radicals to chain react and probably making interesting and unhealthy things.

                  My apologies, I’m out of the lab and field 15 years now so, do make some pretty basic mistakes at times.

    • Arcity 🇵🇸🇺🇦@feddit.nl
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      7 months ago

      Nothing, because you can have only one atom of it. Multiple will just form molecular hydrogen H2. That one hydrogen atom will aggressively rip of another hydrogen of a molecule of water for example, but it won’t be noticeable.